POLYGON AND CIRCLE EXERCISES |
QUESTIONS
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1/ Find the length of the arc AB and the area of the sector AOB. (click for explanation)
Write the formula for arc length and sector area in each solution.
( solution a, solution b, solution c)
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2) a) The area of a 40^{ 0} sector of a circle is 15.6 dm^{2}. Find the area of whole circle.
b) Find the area of a sector of a circle formed by an angle of 72^{0} if the area of the
whole circle is 255 cm^{ 2}.
c) Circle center O has a diameter of 12 cm. Find:
1) the circumference | 2) the area |
3) Find the length of an arc of this circle for a central angle of 72 ^{0} . | |
4) Find the area of the sector. | (click for solution) |
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3) a) A regular hexagon has an area of 24 cm ^{2} and the apothem measures 3 cm.
1) How long is each side? | 2) What is the perimeter of this hexagon? |
b) Find the area of a regular nonagon if the length of a side is 5.3 dm and the length of a line connecting the center to a vertex is 7 dm.
c) Find the area of the following regular polygons:
1) pentagon: side = 8.2 m, apothem = 5 m. | 2) hexagon: side = 9.4 dm, apothem = 3.2 dm. |
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4) Explain how you would construct a regular hexagon with sides of 7 cm.
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5) Find the measure of each interior and exterior angle for:
a) A regular decagon. | b) A regular dodecagon (12 sides) | c) A regular septagon. |
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SOLUTIONS
A central angle of 360° makes an arc of 2or units,
so a central angle of x° makes an arc of
units.
Since a central angle of 360° makes the area = o r² units²,
the area of a sector with central angle equal to x° is
units².
a) arc AB = 12.28 cm.
sector area = 39.3 cm² |
b) arc AB = 10.38 cm. sector area = 88.27 cm² |
c) arc AB = 52.33 dm. sector area = 654.5 cm² |
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2)
a) Since 40° is one ninth of a full circle, the total area = 9 ( 15.6) = 140.4 cm².
b) Since 72° is one fifth of a full circle, the sector area = 1/5 ( 255) = 51 cm².
c) diameter = 12 cm. so radius = 6 cm.
1) the circumference = od = 12o = 37.68 cm. | 2) the area = or² = 36o = 113.04 cm². |
3) arc for a central angle of 72 ^{0} = 7.54 cm. | 4) Find the area of the sector = 22.61 cm². |
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3) a) A regular hexagon with area = 24 cm ^{2}, apothem = 3 cm.
1) side = 2.67 cm | 2) perimeter = 16 cm. |
b) area of nonagon if side = 5.3 dm and radius = 7 dm.
Use Pythagoras to solve for the apothem = 6.48 dm. so area = 154.55 dm².
c) Find the area of the following regular polygons:
1) pentagon: side = 8.2 m, apothem = 5 m. Area = 1025 m². |
2) hexagon: side = 9.4 dm, apothem = 3.2 dm. Area = 90.24 dm². |
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4) A hexagon has 6 sides. We draw a line segment and mark off AB = 7 cm.
Since each interior angle of a regular hexagon = 120°, we construct a 120° angle
at both A and B. Then we measure 7 cm to C on the right and F on the left. We contiinue
the process until we complete the hexagon.
5) Find the measure of each interior and exterior angle for:
a) A regular decagon. interior = 144° |
b) A regular dodecagon (12 sides) interior = 150° |
c) A regular septagon. interior = 128.57° |
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