436 - 5 End of Exam Questions |

**Cyber Students,**

Here are 5 questions from the end of former finals (part C) .

The first one is **extremely** easy, can be done with a single calculation,

so don't believe that the hard ones are at the end.

Go to it:

1)The image represents the path of a dolphin both in water and out as it performs a trick.

The curves *f *(*x*)* *and* g *(*x*)* *are parabolas.

the rule represents the dolphin's path in the water.

The maximum height of the jump out of water is 4 meters.

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2)

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3)

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4)

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5)

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**Solutions**

1) *g*(*x*)* = – *(*x –* 8)² + 4

2) angle BPC = 65° (corresponding angles)

therefore (2*x* + 3*x* + 65)° = 180°, which makes *x* = 23°

so angle = 2*x* = 46°

3) Use the distance formula to find the lengths of the 3 sides,

then use Cosine law to find the angle.

you should get cos C = 0.7894 so C = 37.87°

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4) Use law of sines on triangle SMG to find SG = 9.97 meters

use trig definition of sine on right triangle SGN to find *SN = h = 9.97(sin 70°) = 9.37 m.*

*A = ½bh = ½(2 m)(9.37 m) = 9.37 m² *so answer is* **9.4 m²*

*.*

5)

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