Solutions: Calculus II Test #3

A/ INTEGRATE

1)

Let u = x + 4, then du = dx

and 3x + 2 = 3u – 10

 
 

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2)

Let u = x – 3, then du = dx
 

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3)

Let x = u12
dx = 12u11 du, then divide

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4)

 

u = 4 + x1/2 ,
u – 4 = x1/2
dx = 2(u – 4)du

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B/ Limits

1) 12 2) º 3) 0 4) e0 = 1 5) 0 6) – ½

C/ Convergence

1) º diverges 2) o/2 converges 3) – 9/2 converges 4) diverges 5) 1/(ln 2) converges

(Calculus II MathRoom Index)

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