CALCULUS I TEST #1 SOLUTIONS

Time limit:

Instructions:

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Show all work. Write neatly and big enough to see!!
Numbers in parentheses ( ) are mark values.

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A/ Solve these Inequalities:

1) multiply by 10
15 < 2 - 8x < 35
transpose the 2
13 < - 8x < 33
divide by -8
Solution: -33/8 < x < -13/8

2) | 6x - 7 | > 1
greater than is 2 separate intervals
6x - 7 < -1 and 6x - 7 > 1
solving the 2 inequalities
Solution: x < 1 or x > 4/3.

3)

the zeros are x = -5, 1/3, or 7/5
test the fraction's sign in these intervals,
Solution: -5 < x < 1/3 or x > 7/5

4) x² + 4 m 4x

x² - 4x + 4 m 0
which makes (x - 2) 2
m 0
which is true for all real numbers since
perfect squares are all positive or zero.

Solution: x ` ·

(12)

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B/ Evaluate the Limits:

1) 2)

Now invert and multiply, apply limit = -9

3) 4)
by the theorem, since n is odd,
limit = -
º

5)
    a)
    b)
    c)

6)
    a)
    b)
    c)

(18)

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C/ 1) Differentiate. Do not simplify beyond basic algebra.

a) f '(x) = 3(x 5 - 7x 2)2 (5x 4 - 14x)(3x 4 + 5x) 2 + 2 (3x 4 + 5x)(12x 3 + 5)(x 5 - 7x 2) 3 .

b)

c) f ' (x) = -15(cot 2 5x)(csc 2 5x)(sec 3x) + 3 sec 3x tan 3x cot 3 5x.

d)

(16)

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2) Since the slope of the line 5x - 2y -1 = 0 is 5/2, the derivative must = 5/2
So we know the slope of our tangent. We must find the point of contact.
The derivative y ' = 6x + 4 so we set 6x + 4 = 5/2 and solve for x.
We find x = -1/4 which makes y = -109/16.
We write the equation of the line through this point with slope = 5/2.
Solution: 5x - 2y - 99/8 = 0

(4)

TOTAL (50)

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